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Oracle 1z0-071 certification exam is ideal for professionals who are involved in managing and manipulating data within Oracle databases. These professionals include database administrators, developers, data analysts, and database architects. Passing 1z0-071 exam not only validates their skills and knowledge in SQL and Oracle databases, but it also opens up new career opportunities and advancement prospects.
NEW QUESTION # 92
Examine the structure of the PROGRAMS table:
Which two SQL statements would execute successfully?
- A. SELECT TO_DATE (NVL (SYSDATE-END_DATE, SYSDATE)) FROM programs;
- B. SELECT NVL (MONTHS_BETWEEN (start_date, end_date), 'Ongoing') FROM programs;
- C. SELECT NVL (TO_CHAR (MONTHS_BETWEEN (start-date, end_date)), 'Ongoing') FROM programs
- D. SELECT NVL (ADD_MONTHS (END_DATE,1) SYSDATE) FROM programs;
Answer: C,D
NEW QUESTION # 93
Which two queries execute successfully?
- A. SELECT SYSTIMESTAMP + INTERVAL '1' DAY FROM DUAL;
- B. select INTERVAL '1' DAY +INTERVAL '1' MONTH FROM DUAL;
- C. SELECT SYSDATE "INTERRVAL '1' DAY FROM DUAL;
- D. SELECT INTERVAL '1' DAY - SYSDATE FROM DUAL;
- E. SELECT INTERVAL '1' DAY - INTERVAL '1' MINUTE FROM DUAL;
Answer: A,E
Explanation:
A: This statement will not execute successfully because you cannot subtract a DAY interval from a DATE directly. SYSDATE needs to be cast to a TIMESTAMP first.
B: This statement is correct. It adds an interval of '1' DAY to the current TIMESTAMP.
C: This statement is correct. It subtracts an interval of '1' MINUTE from '1' DAY.
D: This statement will not execute successfully. In Oracle, you cannot add intervals of different date fields (DAY and MONTH) directly.
E: This statement has a syntax error with the quotes around INTERVAL and a misspelling, it should be 'INTERVAL'.
Oracle Database 12c SQL supports interval arithmetic as described in the SQL Language Reference documentation.
NEW QUESTION # 94
Examine the description of the MEMBERStable:
Examine the partial query:
SELECT city, last_name LNAME FROM members ...;
You want to display all cities that contain the string AN. The cities must be returned in ascending order, with the last names further sorted in descending order.
Which two clauses must you add to the query? (Choose two.)
- A. WHERE city = '%AN%'
- B. ORDER BY 1, LNAME DESC
- C. WHERE city LIKE '%AN%'
- D. ORDER BY last_name DESC, city ASC
- E. ORDER BY 1, 2
- F. WHERE city IN ('%AN%')
Answer: B,D
Explanation:
Explanation/Reference: https://www.techonthenet.com/sql/order_by.php
https://www.studytonight.com/dbms/orderby-clause.php
NEW QUESTION # 95
Examine this statement,which executes successfully:
In which order are the rows displayed?
- A. Sorted by MAXSAL
- B. sorted by DEPARTMENT_NAME and MAXSAL
- C. sorted by DEPARTMENT_NAME and AVGSAL
- D. sorted by DEPARTMENT_NAME
- E. sorted by AVGSAL
Answer: C
Explanation:
Since the statement seems to imply that a sort operation involving department names and an average salary (AVGSAL) was executed, the best logical inference, given typical SQL query behavior and assuming a typical structure, is:
* B. sorted by DEPARTMENT_NAME and AVGSAL: Generally, when SQL queries involve grouping and aggregation, the ORDER BY clause (if explicitly mentioned or implied in your statement details) would sort by the grouping column first (DEPARTMENT_NAME) and then by any aggregated column such as average salary (AVGSAL). This order ensures that within each department, the rows are sorted according to the average salary.
NEW QUESTION # 96
View the Exhibit and examine the structure of the ORDERS table.
The columns ORDER_MODE and ORDER TOTAL have the default values'direct "and respectively.
Which two INSERT statements are valid? (Choose two.)
- A. INSERT INTO orders VALUES (1, '09-mar-2007', 'online',' ',1000);
- B. INSERT INTO orders (order_id, order_date, order mode,customer_id, order_total) VALUES (1, TO_DATE (NULL),'online',101, NULL) ;
- C. INSERT INTO orders VALUES('09-mar-2007',DEFAULT,101, DEFALLT);
- D. INSERT INTO (SELECT order_id, order date, customer_id FROM orders) VALUES (1, '09-mar-2007",101);
- E. INSERT INTO orders (order id, order_date, order mode, order_total)VALUES (1,'10-mar-2007','online', 1000)
Answer: C,D
NEW QUESTION # 97
The PRODUCT_INFORMATION table has a UNIT_PRICE column of data type NUMBER(8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price,'$9,999') FROM PRODUCT_INFORMATION;
Which two statements are true about the output?
- A. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,024.
- B. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as #####
- C. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,023.
- D. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,023.
- E. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,0236.
Answer: B,D
Explanation:
The TO_CHAR function is used to convert a number to a string format in Oracle SQL. In this format mask '
$9,999', the dollar sign is a literal, and the 9 placeholders represent a digit in the output. The comma is a digit group separator.
A). This statement is incorrect because the format model does not have enough digit placeholders to display the full number 1023.99; it would round it to $1,023 not $1,024. B. This statement is correct. Given the format '
$9,999', the number 1023.99 will be formatted as $1,023 because the format rounds the number to no decimal places. C. This is incorrect because the format '$9,999' cannot display the number 10235.99; it exceeds the format's capacity. D. This is incorrect for the same reason as C, and the format would not change the thousands to hundreds. E. This statement is correct. If the number exceeds the maximum length of the format mask, which is 4 digits in this case, Oracle SQL displays a series of hash marks (#) instead of the number.
These formatting rules are described in the Oracle Database SQL Language Reference, which covers the TO_CHAR function and its number formatting capabilities.
NEW QUESTION # 98
Examine these statements which execute successfully:
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24 MI: SS'
ALTER SESSION SET TIME_ ZONE = '-5:00';
SELECT DBTIMEZONE, SYSDATE FROM DUAL
Examine the result:
If LOCALTIMESTAMP was selected at the same time what would it return?
- A. 11-JUL-2019 6,00,00,000000 AM
- B. 11-JUL-2019 11,00,00,000000AM -05:00
- C. 11-JUL-2019 6,00,00,00000000 AM - 05:00
- D. 11-JUL-2019 11,00,00,00000000 AM
Answer: D
NEW QUESTION # 99
Examine the structure of the SHIPMENTS table:
You want to generate a report that displays the PO_IDand the penalty amount to be paid if the SHIPMENT_DATEis later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
Which statement is true regarding the above commands?
- A. Both execute successfully and give correct results.
- B. Only the first query executes successfully and gives the correct result.
- C. Only the first query executes successfully but gives a wrong result.
- D. Only the second query executes successfully and gives the correct result.
- E. Only the second query executes successfully but gives a wrong result.
Answer: B
NEW QUESTION # 100
View the exhibit and examine the structure of the PROMOTIONS table.
You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?
- A. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');
- B. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE promo_category = 'INTERNET');
- C. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');
- D. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions) ANDpromo_category= 'INTERNET';
Answer: B
NEW QUESTION # 101
Examine the description of the CUSTOMERS table:
Which three statements will do an implicit conversion?
- A. SELECT * FROM customers WHERE insert_date'01-JAN-19';
- B. SELECT * FROM customers WHERE customer_id=0001;
- C. SELECT * FROM customers WHERE TO_CHAR(customer_id)='0001';
- D. SELECT * FROM customers WHERE customer_id='0001';
- E. SELECT * FROM customers WHERE insert_date=DATE'2019-01-01';
- F. SELECT * FROM customers WHERE TO_DATE(insert_date)=DATE'2019-01-01';
Answer: A,D,F
NEW QUESTION # 102
Which three privileges can be restricted to a subset of columns in a table? (Choose three.)
- A. UPDATE
- B. ALTER
- C. INSERT
- D. DELETE
- E. SELECT
- F. INDEX
- G. REFERENCES
Answer: A,D,E
Explanation:
Explanation
NEW QUESTION # 103
Examine the structure of the ORDERS table: (Choose the best answer.)
You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,'rr'), SUM(order_total) FROM orders
GROUP BY TO_CHAR(order_date, 'yyyy');
Which statement is true regarding the result?
- A. It executes successfully and gives the correct output.
- B. It returns an error because the TO_CHAR function is not valid.
- C. It return an error because the datatype conversion in the SELECT list does not match the data type conversion in the GROUP BY clause.
- D. It executes successfully but does not give the correct output.
Answer: C
NEW QUESTION # 104
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?
- A. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION; - B. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
- C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date; - D. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;
Answer: C
NEW QUESTION # 105
Examine the structure of the two tables.
Which two queries execute successfully? (Choose two.)
- A. Option B
- B. Option D
- C. Option E
- D. Option A
- E. Option C
Answer: B,E
NEW QUESTION # 106
See the Exhibit and examine the structure of the PROMOTIONS table:
Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:
What would be the outcome?
- A. It generates an error because multiple conditions cannot be specified for the WHEN clause.
- B. It generates an error because NULL cannot be specified as a return value.
- C. It generates an error because CASE cannot be used with group functions.
- D. It executes successfully and gives the required result.
Answer: D
Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END
NEW QUESTION # 107
Which three statements are correct regarding indexes? (Choose three.)
- A. A non-deferrable PRIMARY KEYor UNIQUE KEYconstraint in a table automatically attempts to create a unique index.
- B. For each DML operation performed on a table, the corresponding indexes are automatically updated if required.
- C. Indexes should be created on columns that are frequently referenced as part of any expression.
- D. When a table is dropped, corresponding indexes are automatically dropped.
Answer: A,B,D
Explanation:
Explanation/Reference:
References:
http://viralpatel.net/blogs/understanding-primary-keypk-constraint-in-oracle/
NEW QUESTION # 108
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Oracle 1z0-071 exam is a computer-based exam that lasts for 120 minutes. 1z0-071 exam consists of 73 multiple-choice questions, and the passing score is 63%. 1z0-071 exam is available in different languages, including English, Japanese, Korean, Portuguese, and Chinese. It can be taken at any authorized Oracle testing center or online through Oracle's remote proctoring service.
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