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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. In which two cases would you use an outer join? (Choose two.)

A) The tables being joined have both matched and unmatched data.
B) The tables being joined have only unmatched data.
C) The tables being joined have only matched data.
D) The columns being joined have NULL values.
E) The tables being joined have NOT NULL columns.
F) Only when the tables have a primary key/foreign key relationship.

2. Examine the structure of the EMPLOYEES and NEW EMPLOYEES tables:

Which MERGE statement is valid?

A) name = e.first_name ||','|| e.last_name
WHEN NOT MATCHED THEN
INSERT VALUES(e.employee_id, e.first_name ||',
'||e.last_name);
B) MERGE new_employees c
FROM employees e
ON (c.employee_id = e.employee_id)
WHEN MATCHED THEN
UPDATE SET
C) MERGE new_employees c
USING employees e
ON (c.employee_id = e.employee_id)
WHEN EXIST THEN
UPDATE SET
D) name = e.first_name ||','|| e.last_name
WHEN NOT MATCHED THEN
INSERT VALUES(e.employee_id, e.first_name ||',
'||e.last_name);
E) name = e.first_name ||','|| e.last_name
WHEN NOT MATCHED THEN
INSERT VALUES(e.employee_id, e.first_name ||',
'||e.last_name);
F) MERGE INTO new_employees c
USING employees e
ON (c.employee_id = e.employee_id)
WHEN MATCHED THEN
UPDATE SET
G) name = e.first_name ||','|| e.last_name
WHEN NOT MATCHED THEN
INSERT INTO new_employees VALUES(e.employee_id, e.first_name ||'.'||e.last_name);
H) MERGE INTO new employees c
USING employees e
ON (c.employee_id = e.employee_id)
WHEN EXISTS THEN
UPDATE SET

3. Which view should a user query to display the columns associated with the constraints on a table owned by the user?

A) ALL_CONSTRAINTS
B) USER_CONSTRAINTS
C) USER_COLUMNS
D) USER_CONS_COLUMNS
E) USER_OBJECTS

4. Examine the description of the STUDENTS table:

Which two aggregate functions are valid on the START_DATE column? (Choose two)

A) MIN (start_date)
B) COUNT (start_date)
C) MAXIMUM (start_date)
D) AVG (start_date, end_date)
E) SUM (start_date)
F) AVG (start_date)

5. Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns:

Which statement ensures that a value is displayed in the calculated columns for all employees?

A) SELECT last_name, 12*salary* (commission_pct,0) FROM emp;
B) SELECT last_name, 12*salary* commission_pct FROM emp;
C) SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;
D) SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

Solutions: